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Depletion width, built-in potential and junction capacitance calculator

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KEY POINTS

For an abrupt junction, the depletion width is W = √(2ε(Vbi + VR)/q × (NA + ND)/(NA·ND)). It extends mostly into the lightly doped side and grows with the square root of reverse bias. Junction capacitance Cj = ε/W falls as reverse bias rises. A silicon p⁺n junction with 10¹⁶ cm⁻³ on the n side has a built-in potential of about 0.8 V and a zero-bias depletion width of about 0.3 µm.

Inputs

Depletion width W0.3299µm
Built-in potential Vbi0.8334V
Extent into n side xn / p side xp0.327 / 3.27×10⁻³µm
Maximum field Emax50,500V/cm
Junction capacitance per area Cj31.4nF/cm²
Junction capacitance (area 1 mm²)314pF
Intrinsic carrier concentration ni (at this temperature)1.00×10¹⁰cm⁻³

Calculated with full ionization, an abrupt junction and the depletion approximation. For graded junctions made by diffusion, W scales with the cube root of voltage and is slightly wider than this value.

Reverse bias, depletion width and junction capacitance

00.250.50.7510246810Reverse bias [V]Depletion width [µm]
0510152025300246810Reverse bias [V]Junction capacitance [nF/cm²]

p⁺n junction reference table (NA = 1×10¹⁹ cm⁻³)

Calculated for Silicon (Si) at 300 K.
ND (cm⁻³)Vbi (V)W (0 V, µm)W (10 V, µm)Cj (10 V, nF/cm²)
1.0×10¹⁴0.7743.16311.8040.878
1.0×10¹⁵0.8331.0383.7432.77
1.0×10¹⁶0.8930.3401.1878.72
1.0×10¹⁷0.9520.1120.37827.4
1.0×10¹⁸1.0120.0380.12582.8

Which side the depletion region grows into

The depleted charge is equal on both sides of a pn junction (NA·xp = ND·xn), so the depletion region extends mostly into the lightly doped side. In a one-sided junction such as p⁺n, almost all of it lies on the n side, and width and capacitance depend only on the lightly doped side. That is why the drift layer of power devices, which must withstand high voltage, is lightly doped and thick.

Under reverse bias, the depletion region widens with the square root of voltage and junction capacitance falls with the inverse square root. Varactors (variable capacitance diodes) use this effect, and plotting 1/C² against voltage gives the doping of the lightly doped side from the slope (C-V doping profiling).

FAQ


Why does the depletion region extend into the lightly doped side?

The depleted charge must balance on both sides (NA·xp = ND·xn), so the side with fewer dopants must be depleted over a longer distance.

How is doping measured from capacitance?

Plotting 1/C² against reverse bias gives a line whose slope yields the doping of the lightly doped side (C-V profiling).

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Last updated: October 23, 2026